a clock hangs on the wall of a railway station,71ft 9in long and 10ft 4in high.those are the dimension of the wall,not the clock!while waiting for a train we noticed that the hands of the clock were pointing in opposite directions,and were parallel to one of the diagonals of the wall,what was the exact time ?

• it can have four possiblities
  time could be
  7:5
  1:35
  11:25
  5:55
• 12 years agoHelpfull: Yes(8) No(6)
• Let us determine a diagonal of the wall
  
  10 ft 4 inches = 124 inches
  and
  71 ft 9 inches = 861 inches
  
  the tangent of the angle between the
  bottom and top and a diagonal is
  
  124/861
  
  the inverse tangent of this is 8.1953°
  
  thus the hour hand would have to be
  at an angle of 81. 80469° to the
  right of 12 o' clock high if the time is
  ANY where between 12 and 3 in order
  for this premise to be true.
  
  At 3:00 it is at 90° and at 12:00 it is at zero.
  
  The hour hand reaches this parallel position at
  
  81.80469357
  ▬▬▬▬▬▬ X 3 hours
  90
  
  which is
  
  2.726823119 hours after 12
  
  or
  
  43.60938714 minutes after 2:00
  
  or 2:43:36
  
  I just verified that the minute hand would be at an angle of
  
  261.6563228° at that time which is
  81.65° away from the 6:00 position so it would, appear directly
  opposite and within that minute, should be directly opposite the hour
  hand.
  
  Although that could round to 2:44, the exact time HAS not reached 2:44 yet
  during the 2:43 minute.
  
  
  so the time could be 2:43
• 12 years agoHelpfull: Yes(7) No(5)
• pls can any 1 explain clearly
• 10 years agoHelpfull: Yes(2) No(0)
• 1:35
  or
  7:25
• 12 years agoHelpfull: Yes(1) No(3)