the egg vendor calls on his 1st customer and sells his half his eggs and half an egg.to the 2nd customer he sells half of what he had left and half an egg,and to the 3rd customer he sells half of what he had then left and half an egg.by the way he did not break any eggs.in the end 3 eggs were remainig.how many did he start out with?

• He start out with 31eggs.
  
  In the end, he have 3eggs left.
  So,
  3*2 +1= 7
  7*2 +1= 15
  15*2 +1= 31
  
  31eggs he had initially.
• 12 years agoHelpfull: Yes(29) No(3)
• let initially the vendor has x no. of eggs
  sold left with
  1st customer (x/2)+(1/2) (x/2)-(1/2)=(x-1)/2
  2nd (x-1)/4+(1/2) (x-1)/4-(1/2)=(x-3)/4
  3rd (x-3)/8+(1/2) (x-3)/8-(1/2)=(x-7)/8
  
  as finally he left with 3 eggs, (x-7)/8=3
  therefore x=24+7=31
• 12 years agoHelpfull: Yes(9) No(0)
• 31 IS THE ANS
  31/2 + 1/2 =16 (1ST); 15 LEFT
  15/2 + 1/2=8 (2nd); 7 LEFT
  7/2 + 1/2=4 (3rd) ; 3 LEFT
  total=31
• 12 years agoHelpfull: Yes(9) No(0)
• 24 eggs he had.
  
• 12 years agoHelpfull: Yes(3) No(16)
• i'm not sure i think its 31
• 12 years agoHelpfull: Yes(2) No(5)
• hi vignesh, how +1 will come? i.e.,3*2+1=7
  
• 10 years agoHelpfull: Yes(2) No(1)
• ans is 24
  24/2=12(1st customer)
  12/2=6(2nd customer)
  6/2=3(3rd customer)
  so at last he had left 3 eggs
  ans is 24
• 10 years agoHelpfull: Yes(1) No(1)