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Maths Puzzle
let S is a set of all natural numbers less than 120 such that HCF of any element in S and 120 is 1. Find the sum of all elements in S?
A. 7640 B. 6460
C. 7240 D. 6780
Read Solution (Total 4)
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- 1584 is the sum of all elements is S.
Given options are all wrong.
S is a set of all natural numbers less than 120 such that HCF of any element in S and 120 is 1.
Such numbers are,
S = {1, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113}
Sum of S = 1584.
S = Prime numbers (5 - 12 years agoHelpfull: Yes(5) No(1)
- My Solution is not visible fully. That why I post again and again.
Reason for my solution :
We take Only prime numbers because, other than the prime numbers all other natural numbers along with 120 are divisible by any of the natural numbers. So only, we consider prime numbers.
In prime numbers, 2 3 and 5 are not consider. Because those numbers are divisors of 120.
S = Sum of{[prime number(greater than 5 and less than 120}]+1} - 12 years agoHelpfull: Yes(1) No(0)
- 1584 is the sum of all elements is S.
Given options are all wrong.
S is a set of all natural numbers less than 120 such that HCF of any element in S and 120 is 1.
Such numbers are,
S = {1, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113}
Sum of S = 1584.
S = sum of [Prime numbers (5 - 12 years agoHelpfull: Yes(0) No(0)
- 1584 is the sum of all elements is S.
S = sum of [Prime numbers (5 - 12 years agoHelpfull: Yes(0) No(0)
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