there are 10 coins.6 coins showing head,4 coins showing tail.10 coins are flipped(not tossed)randomly 7 times successively.now 5 coins are showing head and 4 tails.1 coin is hided.hided coin will show which side?

• This question does not make sense!
  
  If a coin is "flipped" and is not tossed it changes from a head to a tail or from a tail to a head.
  If you therefore flip a coin 7 times, if it started as a head, it will finish as a tail/ If it started as a tail it will finish as a head. An odd number of flips means it "turns over" an even number and it stays the same way up,
  
  Therefore if each coin is "flipped" seven times you will end up with 6 tails and 4 heads. Therefore to have 4 tails and 5 heads showing is IMPOSSIBLE.
  
  Therefore I have to assume that you DO NOT MEAN "FLIPPED", but mean "tossed".
  
  If you toss a coin it is a 50/50 probability that you get a head or a tail whether you have tossed it 7 times previously or 7 million times previously, the probability doesn't change.
• 12 years agoHelpfull: Yes(17) No(9)
• After flipping the coins , there are 6 heads and 4 tails..
  (the hided coin will have head)
• 12 years agoHelpfull: Yes(8) No(10)
• ans is tail. bcoz after flipping coins should have at least 5 head and 4 tails.
• 11 years agoHelpfull: Yes(2) No(0)
• the hidden coin will be heads.. since the coins are flipped... head->tail nd vice versa
• 11 years agoHelpfull: Yes(1) No(1)
• can not be predicted bczc prob of gtin hd or tl is 50-50.
• 11 years agoHelpfull: Yes(0) No(0)