If two pipes function simultaneously, tbe reservoir will be filled in 12 hours. One pipe fills the reservoir 10 hours faster than tbe otber. How many hours does it take the second pipe to fill the reservoir?

• let the reservoir be filled by first pipe in x hours.
  
  Then ,second pipe fill it in (x+10)hrs.
  
  Therefore (1/x)+(1/x+10)=(1/12) (x+10+x)/(x(x+10))=(1/12).
  
  x^2 –14x-120=0 => (x-20)(x+6)=0
  
  
  x=20 [neglecting the negative value of x]
  
  so, the second pipe will take (20+10)hrs. (i.e) 30 hours to fill the reservoir
  
• 12 years agoHelpfull: Yes(5) No(2)
• Dear Chaitynya,
  
  If u want to post yourself and sumit answer yourself, it is better if you sumit the questions as Unknown user.
  Have fun anyway.
• 12 years agoHelpfull: Yes(5) No(2)
• Both Kumar and Chaitanya are same person with different logins???
  
  So, Chaitanya itself post the questions in the name of Kumar and answer for that as Chaitanya!!
  
  Any use on that??
• 12 years agoHelpfull: Yes(3) No(0)
• I was surprised why Kumar is bothered/not bothered on behalf of chaitanya.
  
  I think he has forgotten that he has logged in as Kumar now.
  
  Good luck Chaitanya/kumar.
• 12 years agoHelpfull: Yes(2) No(0)
• Really smart 'mathematician'.
  
  Keep it up. :-)
• 12 years agoHelpfull: Yes(2) No(0)
• @ AMAN
  
  i'm not bothered about u'r skill
  i just want o bring out the reason thats it
  
  if it hurts u i'm sry
  
  
  from now i'll just concentrate on the unsolved
  
  
• 12 years agoHelpfull: Yes(1) No(3)
• the mystery of CHAITANYA and KUMAR is more interesting then que..:)
  
  well done vignesh for solving it..
• 11 years agoHelpfull: Yes(0) No(0)