A bag contains 50 p 25 P and 10 p coins in the ratio 5 9 4 amounting to Rs

Let the number of 50 p, 25 P and 10 p coins be 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10) = 206
50x + 45x + 8x = 4120
1O3x = 4120
x = 40.

Number of 50 p coins = (5 x 40) = 200;
Number of 25 p coins = (9 x 40) = 360;
Number of 10 p coins = (4 x 40) = 160.
12 years agoHelpfull: Yes(10) No(7)
let 50p,25p and 10p coins be 5x,9x & 4x respc.
now divide the no. of coins by their denomination related to the rupee
So,
(5x/2)+(9x/4)+(4x/10)=206
50x + 45x + 8x =206*20
1O3x =206*20
therefore,
x = 40.
Therefore,
50p coins=(5 x 40)=200;
25p coins=(9 x 40)=360;
10p coins=(4 x 40)=160.
12 years agoHelpfull: Yes(8) No(5)
50p-200,25p-360,10p-160
12 years agoHelpfull: Yes(0) No(1)
Good observation by Vignesh.
12 years agoHelpfull: Yes(0) No(0)
et ratio be x,
hence no. of coins be 5x ,9x , 4x respectively
now given total amnt = Rs.206
=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206
=> on solving
we get x = 40
=> no. of 50p coins = 200
=> no. of 25p coins = 360
=> no. of 10p coins = 160
10 years agoHelpfull: Yes(0) No(0)

A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206.

Find the number of coins of each type