GRE
Exam
Numerical Ability
Geometry
The sum of the interior angles of any polygon with n sides is 180(n–2) degrees. If the sum of the interior angles of polygon P is three times the sum of the interior angles of quadrilateral Q,how many sides does P have?
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- 8 sides
The sum of the interior angles of any polygon with n sides is 180(n-2) degrees.
sum of the interior angles of polygon P =3*( sum of the interior angles of quadrilateral)= 3*360 degrees
180(n-2) = 3*2*180
n-2=6
n=8 - 12 years agoHelpfull: Yes(5) No(1)
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