If x,y, and z are positive integers and 3x=4y=7z, then the least possible value of x+y+z is
(A) 33
(B) 60
(C) 49
(D) 61

• 3x=4y=7z
  
  LCM of 3,4,7 is 84.
  so
  3x=4y=7z=84
  so min value of
  x= 28,y=21,z=12
  min x+y+z= 28+21+12=61
• 11 years agoHelpfull: Yes(13) No(0)
• x+y+z=x(1+3/4+3/7)=33x/28
  x+y+z is an integer.
  33x/28 is an integer . so minimum valu of x=28
  so y=21 and z=12
  so x+y+z=28+21+12=61 is the least possible sum
• 11 years agoHelpfull: Yes(5) No(3)
• d)61 is the least possible value of x+y+z.
  
  x=28 ; y=21 ; z=12
  
  3x=4y=7z
  --> 3(28)=4(21)=7(12)
  --> 84=84=84
  
  X+Y+Z = 28+21+12 = 61
• 11 years agoHelpfull: Yes(2) No(2)
• 61 is the least possible value,
• 11 years agoHelpfull: Yes(0) No(3)