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Maths Puzzle
three cakes weighing 5.25 kg, 7.75 kg and 8.20 kg are to be cut into pieces such that they have equal weight and each piece has the maximum possible weight. Find the number of guests who can be served, if one piece is served to each of them.
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- 424 guests totally.
HCF of 5.25, 7.75 and 8.20 = 0.05
So, (5.25/0.05 + 7.75/0.05 + 8.20/0.05) = (105+155+164) = 424
424 guests totally
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