If one side of a right-angled triangle is two more than the second side and the hypotenuse is four more
than the shorter side, find the lengths of all sides of the triangle.

• Let one side of a right angled triangle is "x"
  The other side is x+2 , and
  the hypotenuse is x+4
  Using Pythogoreous theorem:
  x^2+(x+2)^2=(x+4)^2
  Simplifying, we get the Quadratic equation
  x^-2x=16
  Using completing the square method
  we get (x-1)^2=17
  x=1+sqrt17
  The other side is 3+sqrt17(2 more)
  and the hypotenuse is 5+sqrt17
• 12 years agoHelpfull: Yes(0) No(0)