If one side of a right-angled triangle is one less than the other and the hypotenuse is twice the shorter
side, find the lengths of all sides of the triangle

• Let one side of a right angled triangle be "x"
  The other side is (x-1), and
  Hypotenuse is 2x-2
  USING PYTHOGOREOUS THEOREM
  x^2+(x-1)^2=(2x-2)^2
  x^2+x^2+1-2x=4x^2+4-8x
  Simplifying this we get the Quadratic equation:
  x^2-3x=3/2
  solving this we get the value of 'x' AS (3+sqrt3)/2
  the other side is less by 1, and hence the side is (1+sqrt3)/2
  and the hypotenuse is 1+sqrt3(2 times the shorter side
• 12 years agoHelpfull: Yes(1) No(0)