find the last digit in the expansion of 3^100?

• last digit of 3^1=3
  last digit of 3^2=9
  last digit of 3^3=7
  last digit of 3^4=1
  last digit of 3^5=3
  last digit of 3^6=9
  so again repeat the same number. Cyclic is 4
  100/4 = 25 remainder is zero.
  Remainder zero means that is in 4th Cycle. That is last digit is 1.
• 12 years agoHelpfull: Yes(10) No(4)
• 1 is the answer. 3^100= 81^25 which has one at last place
• 12 years agoHelpfull: Yes(4) No(5)
• 1 as
  3^(3n+1) has last digit as 1
  here 100= 3*33 +1 for n=33
  so 3^100 has 1 at unit place
• 12 years agoHelpfull: Yes(3) No(4)
• answer is 1
  bcz
  3^(3n+1) has last digit as 1
  here 100= 3*33 +1 for n=33
  so 3^100 has 1 at unit place
• 12 years agoHelpfull: Yes(2) No(5)
• ans 1
  3^100
  
  3^4(25)
  x^4=1
  so, 3^4=1
  1^25 =1
• 12 years agoHelpfull: Yes(0) No(0)
• 1
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
• 11 years agoHelpfull: Yes(0) No(1)