A ladder 15 m long reaches a window which is 9 m above the ground on one side of a

from right angle triangle properties..total width is 12+9=21m
11 years agoHelpfull: Yes(8) No(9)
here there are 2 triangles
one having height=9m & hypotenuse=15m
now the fist side of the street has width=12m by right angle property
now on the other side
height=12
hypo.=15
so width of street=9
total width of street=12+9=21
9 years agoHelpfull: Yes(2) No(0)
Ans =11m.
from the quation a right angle triangle formed in which p is 12 and and h=15.
now from h^2= p^2+b^2
from that b=11 that is width of street.
11 years agoHelpfull: Yes(1) No(6)
9 cm no use mentioned from same point only one triangle

12cm ht of triangle and 15cm hypotenuses of triangle

15^2=12^2-x^2
9 years agoHelpfull: Yes(1) No(0)
we have length of ladder=15m
the base of ladder is kept 9m above from ground
top of ladder is kept 12m above ground which is on other side of street
3 |_15
9 |_|9
therefore lower end forms rectangle
12-9=3m
by PGT
b=(15*15=3*3)^1/2
b=15.297m
hence width of street is 15.297m
11 years agoHelpfull: Yes(0) No(7)
15-9=6
15-12=3
The street length is 6+3=9.
11 years agoHelpfull: Yes(0) No(6)
√(15²−12²)=9
√(15²−9²)=12 so 9+12 = 21.
7 years agoHelpfull: Yes(0) No(0)

A ladder 15 m long reaches a window which is 9 m above the ground on one side of a street.Keeping its foot at the same point, the ladder is turned to other side of the street to reach a window 12 m high. Find the width of the street.