Elitmus
Exam
Category
is x>y
1. 5x+15y=40
2.7x+21y=56
data sufficency elitumus question
Read Solution (Total 9)
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- Answer (d)
infinite solutions so cant be determined - 9 years agoHelpfull: Yes(14) No(2)
- both lines are parallel .......ans (d)....we can't answer even using both the stmt
if u multiply first 1 with 7 and second with 5 then you will find 0 after subtracting them - 9 years agoHelpfull: Yes(3) No(0)
- Since there's two variables and two equation so.. both 1) and 2) are required to answer.
- 9 years agoHelpfull: Yes(1) No(14)
- @vikas jha
see both equations..both are same x+3y=8
so we cant solve
and it is also true for x=y=2
so ans will be (d) - 9 years agoHelpfull: Yes(1) No(0)
- only one is required either 1 or 2
x=5,y=1
because x>y - 9 years agoHelpfull: Yes(1) No(0)
- Yep.. Sorry that was my mistake. Can't be determined even using both the equation.
- 9 years agoHelpfull: Yes(1) No(0)
- ans (b)
for condition I
5x+15y=40 if y=0 than x=8
if x-9 than y=8/3
in same way for condition II
X=8 and Y=8/3 - 9 years agoHelpfull: Yes(0) No(1)
- both equation are same.
2nd equation is 1.4 times of 1st equation.
thus can't be determined using both equation. - 9 years agoHelpfull: Yes(0) No(0)
- I don't know why you all guys started to find the exact value of X and Y, & hence gave wrong answers.
The question asks for whether, X > Y, which means is it TRUE or FALSE.
So 1st alone is sufficient (2nd is identical to first) to answer the question. Put any value, X will always be greater than Y.
For 1st equation
Zero values:: x= 0, y = 40/15 ; y=0, x= 5 . => x >y
Positive values:: x=1, y = 35/15 ; y=1 , x=5 => x> y
negative values:: x=-1, y = 3 ; y=-1 , x= 11 => x>y - 8 years agoHelpfull: Yes(0) No(2)
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