A and B start from their house at 1Oam. They travel from their house on MG road at 2OKmph and 4Okmph These is a T junction on their path. A turns left at the T junction at 12:00 noon B reaches the T
junction earlier and turns right. Both of them continue travelling till 2 :OOpm What is the distance between A and B at 2:OOpm


150 km /120 km /160 km/ 140 km

• By the data Distance from starting point to T is : 20*2 = 40 kms
  Therefore time taken by B to reach T : 40km/40hmph= 1hr
  So from 11:00AM to 2:00 PM B travels the distance : 40*3 = 120kms
  from 12:00noon to 2:00PM A travels the distance 20*2 = 40kms
  So total distance is 160 kms
• 8 years agoHelpfull: Yes(11) No(1)
• easiest way with no confusion..
  1) A started at 10 am at 12 noon he covers 40 k.ms (i.e covers 20 km per hour)
  B started at 10 am at 12 noon he covers 80 k.ms (i.e covers 40 km per hour)
  so at 12 noon distance between them is 80-40= 40 k.m ( since same direction)
  2) now A started at 12 p.m at 2 p.m he covers 40 k.m
  B started at 12 p.m at 2 p.m he covers 80 k.m
  since they are travelling in opposite direction there distance increases i.e added
  so distance b/n them is 40+80=120.
  so total distance between them is ( distance between them at 12p.m + distance between them at 2 p.m)
  finally it becomes 40+120=160
  
• 8 years agoHelpfull: Yes(6) No(0)
• 160km......both started at 10 o clock then b reches at junction T at 11.00....hence B cover 40*3= 120 distance to its right upto 2.00........and A reach junction T at 12.00 cover 40 km....after that he turn left and cover 20*2=40 km distance....hence both are 120+40=160km from each other.
• 8 years agoHelpfull: Yes(4) No(4)
• Ans) 160km
  because A speed is 20km per 1hr so he would be reached T jn. at 12.00 noo ie A travels 40km for 2 hours
  similarly B speed is 40km per hour so he reached T jn. at 11.00 am so he reached the total distance is from T jn. is 120km and A traveled distance is from T jn. is 40km so total distance between A & B is (20+20)+(40+40+40)=160km
  
• 8 years agoHelpfull: Yes(1) No(1)
• Ans is 160km.
  A reaches T junction at 12:00 noon at speed of 20kmph but B has 40kmph(2*20) so B will reach in half time of A at T junction so at 11:00 noon B reach at T junction. Both are travels till 2 pm so A travel aat left for 2 hours and B travel at right for 3 hours.
  So that A travels 40km (2 hours at 20kmph) at left of T junction and B travels 120km (3 hours at 40kmph) at right.
  So total distance 40km+120km=160km.
• 8 years agoHelpfull: Yes(0) No(1)
• A,B(A's speed= 20 KMPH & B's speed= 40KMPH) at 10am-------------------12am-------------------
  at 12 noon A turn left , and distance covered 40km
  B also cover 80km , 40km on straight and 40km on right way and another 2 hr also B cover 80km ,,,,, total is 40+80=120
  A cover 40km on left way
  hence on straight line total distance is 120+40= 160 ans
  
• 8 years agoHelpfull: Yes(0) No(2)
• A starts from starting point at 10 am.both travelled in same road.after 2 hours A could have taken left..in 2 hours A would have completed 40 KMS..so the distance between A and junction is 40..so B also travelled 40 KMS..and extra for 3 hours and completed 120 KMS after turn..now A is 40KMS apart from junction..and B is 120 KMS from junction.. toatal distance will be 40+120=160kms
• 7 years agoHelpfull: Yes(0) No(0)
• from 12 to 2,the time diff is 2hrs.
  d1=t1*s1=2*40=120
  d2=t2*s2=2*20=40
  D=d1+d2=120+40=160km.
• 4 years agoHelpfull: Yes(0) No(0)