Mr A,a cashier at xyz ltd while distributing salary adds whatever money is needed to make the sum a multiple of 50 he adds rs.10 and rs. 40 to a's and b ’s salary respectively and then he realises that the salaries of a b and c are now in the ratio 4:5:7 the salary of c could be

• lets add the ratio 4+5+7 gives 16
  so the sum would be multiple of 16
  lets assume sum of salary is X*16
  then (X*16) is divisible by 50
  
  1) the smallest number that can be multiplied to 16 in order to make it divisible by 50 is 25, i.e x = 25
  that gives : sum = 25*16 = 400 then possible value of c in this case is : 400*(7/16) = 175
  
  2) the another number that can be multiplied to 16 in order to make it divisible by 50 is 50, i.e x = 50
  that gives : sum = 50*16 = 800 then possible value of c in this case is : 800*(7/16) = 350
  .
  .
  take value of x = 150,200,350....etc because they all are multiple of 50
  .
  And solve as long as your answer doesn't match the option.
  
• 8 years agoHelpfull: Yes(4) No(1)
• let reciprocal quantity is x
  therefore total salary distributed is
  
  4*x + 5*x + 7*x = 16*x
  
  according to question 16*x should be divisible by 50
  
  hence we find the no which is multiple of 16 and divisible by 50
  
  400 is smallest required no
  hence
  16*x = 400
  x = 400/16 = 25
  hence c's salary is
  25*7 = 175
  
  similarly 800, 1200 , 1600 ..........are also required sum of salary and we find c's salary in similar way as found above
  
• 8 years agoHelpfull: Yes(1) No(0)
• As you know the sum of a,b and c salary should be multiple of 16 and their individual salary should be multiple of 50 and also it should be in the ratio 4:5:7,So directly multiple 100 to each of the ratio. Now a's salary will be 400, b's salary will be 500 and c's salary will be 700. This is the least possible scenario. After that you can multiple with any number so as to keep the ratio constant and multiple of 50.
• 8 years agoHelpfull: Yes(0) No(0)
• we have to find value of x that satisfies the following 4 conditions:
  4x/50 =integer ......1(considering a)
  5x/50=integer ......2 (considering b)
  7x/50=integer......3 (considering c)
  16x/50=integer......4 (considering a,b,c sum)
  
  value of x =( 50,.......)
  so minimum value of c=7x=7*50=350
• 8 years agoHelpfull: Yes(0) No(0)