In a two digit , if it is known that thrice its units digit is four less than twice it's ten's digit and its ten's digit is thirteen less than four times it's unit digit, then the number is:



A. 24
B. 46
C. 26
D. 52
E. none

• E. None
  
  Let the number is xy i.e (10x+y).
  The first clause suggests: 3y=2x-4 ----> x= (3/2)y+2 ---(1)
  The second clause suggests: x=4y-13 ---(2)
  Inserting (1) in (2) we get:
  (3/2)y+2 = 4y-13 ------> (5/2)y = 15 ----> y=6 ---(3)
  inserting (3) in (2) we get x=11 ---(4)
  
  Hence it seems the question is wrong as the ten's digit is itself a two digit number. My answer would be E. None
• 7 years agoHelpfull: Yes(0) No(0)