R-SAT
Exam
Category
If the numerator of the fraction is increased by 30% and the denominator diminished by 20%. The value of that fraction is 13/10
Find the original factor?
A. 2/5
B. 10/13
C. 3/5
D. 4/5
E. none
Read Solution (Total 3)
-
- D) 4/5
Solution---
Let the fraction be x/y
According to question, (x+0.3x)/(y-0.2y)=13/10
Solving,x/y=8/10=4/5 - 7 years agoHelpfull: Yes(1) No(0)
- D. 4/5
(x+3x/10)/(y-2y/10)=13/10
(13x/10)/(8y/10)=13/10
x/y= (13/10)*(8/13)= 8/10 = 4/5 - 7 years agoHelpfull: Yes(1) No(0)
- D.
130 of x/80 of y=13x/10y
13x/8y=13x/10
x/y=104/130
x/y=4/5 - 7 years agoHelpfull: Yes(0) No(0)
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