a man and a boy can complete a work together in 24 days.if for the last 6 days man alone does the work then it is completed in 26 days.how long the boy will take to complete the work alone

• (1/m +1/b)= 1/24
  6 days before 26 days =20 days
  so work done in 20 days = 20*(1/24) =5/6
  so work left =1/6
  1/6 of the work is done by the man in 6 days so time required by the man to complete the work alone
  = 1/6 work in 6 days
  1 work = 6*6 =36 days
  so replacing m by 36
  (1/36+1/b) = 1/24
  so 1/b =1/72 therefore b = 72 days
• 7 years agoHelpfull: Yes(13) No(2)
• A boy will take 96 hours for completion of the work
• 7 years agoHelpfull: Yes(3) No(5)
• answer is only 72days.
• 6 years agoHelpfull: Yes(0) No(0)
• Work formula= M1*D1 = M2*D2
  (man+boy)*24=(man+boy)20 + man*6
  24man+24boy=20man+20boy+6man
  4boy=2man
  Ratio =boy/man=2/4 or 1/2
  So,
  Total work=(1+2)*24=72
  Boy will take=72/1=72 days
• 2 years agoHelpfull: Yes(0) No(0)