To pass an examination, 40% marks are essential. A obtain 10% marks less than the pass marks and B obtains 11.11% marks less than A. What ... What percent less than the sum of a's and b's marks should c obtain to pass the exam??

• let the total mark=100
  passing mark=40
  A's mark=40*(100-10)/100=36
  B's mark=36*88.89/100=32
  A+B=68
  40=68*(100-41)/100 (approx)
  0 to 41% any value is the answer
• 7 years agoHelpfull: Yes(0) No(1)