if (HE)^H=SHE,where the alphabets take the values from (0-9) & all the alphabets are single digit then find the value of (S+H+E)?

• S+H+E=13
  
  Here H=2, E=5, S=6, so 25^2 =625
  Hence S+H+E=6+2+5=13
• 7 years agoHelpfull: Yes(0) No(4)
• https://brainly.in/question/8398252
• 5 years agoHelpfull: Yes(0) No(0)
• 25^2 = 625
  s=6
  H=2
  E=5
  6+2+5=13
• 5 years agoHelpfull: Yes(0) No(0)
• H can only be 2 becoz cube of a 2 -digit will not be a 3 digit number and any number below 20 i.e (10-19)^1 is not a 3 digit one so our HE lies in the range 20-29... as H=2 the E should be such that squaring it gives the same number in units place. the possible E values r 2,5,6
  so HE can be 22,25,26 ... from trail and error we can find 25 is only the number that satisfy (25)^=625
• 4 years agoHelpfull: Yes(0) No(0)