TCS
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Numerical Ability
Algebra
A sum of 20706 is distributed amongst A, B and C. A gets 10/123 of what B and C got together and C gets 1/10 of what A and B got together, C's share is (approx)?
Read Solution (Total 1)
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- A+B+C=20706
A== 10/123 (B+C)
C=1/10 (A+B)
to find out C-
solve using the equation of C i.e C=1/10 (A+B)
=> A+B=10C
Substitute A+B=10C into the main equation i.e A+B+C=20706
Thus, 10C+C=20706
=> 11C=20706
=> C=1882.36 which is approximately 1882 - 6 years agoHelpfull: Yes(22) No(0)
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