In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
A. 21 m
B. 26 m
C. 28 m
D. 29 m

• C. 28 m
  
  When, A=100, B=75 => A : B = 4 : 3
  When, B=100, C=96 => B : C = 25 : 24
  So, A : B : C = (4x25) : (3x25) : (3x24) = 100 : 75 : 72
  => When A covers 100 m, C covers 72 m. Therefore A can beat C by 100-72=28 m.
• 5 years agoHelpfull: Yes(6) No(3)
• A=B+25
  B=C+4
  A=C+4+25
  A=C+29
  Ans-29
• 5 years agoHelpfull: Yes(2) No(4)
• if A=100m then B=100-25=75m
  A:B=100:75=4:3
  if B=100m then C=100-4=96m
  B:C=100:96=25:24
  then A:B:C=4:3
  25:24
  =25*4:3*25:3*24=100:75:72
  if A=100m then C=72m
  A can beat C by 100-72=28m
  therefore answer is 28m
• 5 years agoHelpfull: Yes(1) No(0)
• Total 100m race
  A beat B by 25m ...so A reaches destination and B is 25m behind
  B beats C means ...B completes the race and C is behind B by 4m
  So, after B completing the race of 25m towards A , C will be (25-4)m behind A
  So , and is 21m
• 5 years agoHelpfull: Yes(0) No(7)
• A=100
  B=75
  C=72
  Ans=28
• 5 years agoHelpfull: Yes(0) No(0)
• A:B= 100:75
  B:C=100:96
  A:C= A:B × B:C = 4:3 × 25:24
  A:C = 100:72
  so A beat C by 100-72= 28m
• 5 years agoHelpfull: Yes(0) No(0)
• Consider A=100 m;
  so A=25+B, so B=75 m ( 100-25);
  B=4+C, so C= 72 m;
  => A can beat C by 100-72=28 m
• 5 years agoHelpfull: Yes(0) No(0)