M men agree to purchase a gift for Rs. D. If three men drop out how much more will each have to contribute towards the purchase of the gift/

A. D/(M-3) B. MD/3 C. M/(D-3) D. 3D/(M2-3M)

• intial contibution = D/m
  after 3 men drop then contribution =D/M-3
  the amount more to pay in contribution = (D/m-3)-D/m
  =D(m-m+3)/)(m^2-3*m)
  = 3D/(m^2-3*m)
  hence dis correct option
  
• 13 years agoHelpfull: Yes(67) No(6)
• initial contribution = D/M
  final contribution = D/(M-3)
  Difference = D/(M-3) - D/M
  =>Difference =D[{M - (M-3)}/{M X (M-3)}]
  =>Difference= 3D/[M(M-3)]
• 10 years agoHelpfull: Yes(6) No(1)
• option A(D/(M-3)) is the answer
• 13 years agoHelpfull: Yes(4) No(44)
• D) each man initially have to give----------------------- D/M
  after left of 3 person each remaining have to give------ D/(M-3)
  difference = D/M-3 - D/M
  = 3D/M(M-3)
• 9 years agoHelpfull: Yes(4) No(0)
• take example
  5 men give 50Rs
  1 men = 50/5 = 10;
  
  3 go so 50/5-3 = 50/2 = 25;
  
  25 rs for each person now , so extra is
  
  25 - 10 (D/m) = 15;
  
  here d=15, m=5; then it become easy to do above question.
• 8 years agoHelpfull: Yes(2) No(0)