2. Peter and Paul ate two friends. The sum of their ages is 35 years. Peter is twice as old as
Paul was when Peter was as old as Paul is now. What is the preset ate of Peter

• there is simple trick
  divide 35 in ratio 0f 4:3
  so (35*4)/7=20 so age of paul is 20
  (35*3)/7=15 age of paul.
  this is aplicable only for the sum of gae which is multiple of 7(mind it).
• 13 years agoHelpfull: Yes(6) No(3)
• Damn sure ....20 is the answer....
  Present. Past
  Peter. 2x. 35-2x
  Paul. 35-2x. x
  Now diff of their pres n past ages r equal
  We get x as 10. So 2x is 20.....
• 13 years agoHelpfull: Yes(3) No(2)
• its quite simple ... ans is 21..
  21 + 14 = 35 ...
  before 7 years ::::
  21(peter'age)-7 = 2(14(Paul's age)-7)
  
  any other value is not possible
  i hope you understand with this example....
• 13 years agoHelpfull: Yes(1) No(0)
• 28. Is the answer.. present. Past
  Peter. 2x. 35-2x
  Paul. 35-2x. x
  
  Now difference between past n pres of both ages are equal..so
  By solving we get x is 14....but peters pre age is 2x so 28 is answer...
• 13 years agoHelpfull: Yes(0) No(6)