7. How many numbers greater than a lakh can be formed with the numbers 0, 1, 2, 3, 2,4

• ans=((5*6*6*6*6*6)/2!) -1
  from left 1st place can be filled in 5 ways excluding zero
  rest five place can be filled in 6 ways. divide whole by 2! bcz we have two 2's which are identical.subtract 1 from result bcz we have only one case in which we get the no. equal to 100000 but we have to take more than 100000.
  
• 11 years agoHelpfull: Yes(34) No(3)
• ans=6^5-1
  
  all the boxes for 6 digit no. can be filled by 6 ways execpt 1st block it can be filled by 5 ways
  so,
  5*6*6*6*6*6
  now 1 has to be subtracted of becoz from this there will be the case when 100000 occurs but we wnt more thn that.
  so 5*6*6*6*6*6-1
• 11 years agoHelpfull: Yes(33) No(8)
• 5*6^5 - 1 = 5*7776 - 1 = 38880-1 =38879
• 11 years agoHelpfull: Yes(9) No(2)
• 5*6*6*6*6*6
  as 1st place can b filled in 5 ways(xcluding 0)& the rest places can be filled in 6 ways each
• 11 years agoHelpfull: Yes(8) No(4)
• Ans: infinite numbers.
  because question is grater than a lakh but there s no limit upto which we have to find.. So simply infinite number can be made.
  5*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6*6................. upto infinite nmbr..
• 11 years agoHelpfull: Yes(7) No(8)
• without repetition
  total numbers= 6!/2!=360
  minus when 0 is in first place => 5!/2!=60
  
  therefore total no. above lac= 360-60=300 Ans
• 11 years agoHelpfull: Yes(6) No(2)
• ans=480
  4*5*4*3*2*1
• 11 years agoHelpfull: Yes(3) No(11)
• since 2 is given twice and so we hve only 5 different digits including 0.
  first cant be 0 so only 4 ways to fill it and rest all by 5 ways
  
  ans = 4*5*5*5*5*5-1
  =12499
• 11 years agoHelpfull: Yes(2) No(0)
• the answer will be 600,if repeatition is not allowed.
• 11 years agoHelpfull: Yes(1) No(1)
• total numbers can be created - 6!/2!=360(two '2's are there)..
  total number which is less than 100000 = 1*5*4*3*2*1/2!=60 (0 is selected first, then rest 5 nos can be arranged as 5!/2!)
  so, numbers greater than a lakh = 360-60 =300.. for more tips n tricks add me on facebook, mah id-adi1nonly .. good luck
  
• 11 years agoHelpfull: Yes(1) No(0)
• if repeatation is allowerd then...
  4*5*5*5*5*4=10,000
• 11 years agoHelpfull: Yes(0) No(5)
• for a number to be greater than lakh it should be of 6 digits.....1st digit can be any digit except 0...rest digits can be anyone from the given digits...
  5*6*6*6*6*6=38880
• 11 years agoHelpfull: Yes(0) No(2)
• When we take 1,3,4 as lachth term then next 5 digits can arrenged in 5!/2! Ways bcoz 2 is repeated 2 times.
  For 2 as lakhth term last 5 digits all are now different nd can be arrenged in 5! Ways.
  0 cant be lakhth term so total ways are
  3*5!/2!=180
  5!=120
  Total are 300
• 10 years agoHelpfull: Yes(0) No(0)
• Total ways they can be arranged – without 0 at first they can be arranged
  6!/2!=360 -- 5!/2!=60
  300
• 6 years agoHelpfull: Yes(0) No(0)