a ladder of 100m is kept. the difference b/w foot of ladder and wall is 60m. what can be the maximum side of a cube that can be placed between wall and ladder

• draw the diagram,it will be a right angle triangle
  whose sides are 100,60 and 80 (using pythagorous theorem)
  draw a perpendicular from foot of wall to ladder and let it be h
  so 1/2 *80*60 = 1/2 *100*h
  or h=48
  now let x be the max side of cube
  consider a face of cube,it will be a square
  so x^2+x^2=h^2
  or 2*x^2=h^2
  or x^2=(48^2)/2
  or x^2=1152
  or x=33.94 m
• 11 years agoHelpfull: Yes(26) No(3)
• side of cube =sqrt(13600)/2 ans
  
• 11 years agoHelpfull: Yes(1) No(1)
• the expalanation is by diagram. ans 40 m
• 11 years agoHelpfull: Yes(1) No(2)
• tan$=80-x%x=x%60-x.x is the side of cube.solving x=34.28,
• 11 years agoHelpfull: Yes(1) No(0)
• side of cube=33.88(approx)
• 11 years agoHelpfull: Yes(0) No(1)
• Please explain
• 11 years agoHelpfull: Yes(0) No(0)
• it is 33.94 Ans
• 11 years agoHelpfull: Yes(0) No(0)