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1(1!)+2(2!)+3(3!)....2012(2012!) = ?
Read Solution (Total 3)
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- 1(1!)=1 ⇒ 2!-1
1(1!)+2(2!)=1+4=5 ⇒ 3!-1
1(1!)+2(2!)+3(3!)=1+4+18=23 ⇒ 4!-1
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1(1!)+2(2!)+3(3!)+........+2012(2012!)=2013!-1 - 11 years agoHelpfull: Yes(38) No(0)
- we can write above expression in this form..
=(2-1)1!+(3-1)2!+(4-1)3!+.......+(2013-1)2012!
=2!-1!+3!-2!+4!-3!...........+2013!-2012!
=2013!-1! - 11 years agoHelpfull: Yes(10) No(0)
- 1(1!)=1 ⇒ 2!-1
1(1!)+2(2!)=1+4=5 ⇒ 3!-1
1(1!)+2(2!)+3(3!)=1+4+18=23 ⇒ 4!-1
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1(1!)+2(2!)+3(3!)+........+2012(2012!)=2013!-1 - 11 years agoHelpfull: Yes(0) No(0)
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