Q. A and B have their ages in reverse order .the difference in their ages is is twice that of C’s age.B is ten times as old as C.

What are the ages of A,B,C?

• Given A and B have their ages in reverse order
  Let A's age be xy and B's age be yx
  Given the difference in their ages is is twice that of C’s age
  =)(10x+y)-(10y+x)=2c
  =)9(x-y)=2c----(1)
  Given B is ten times as old as C
  =)10y+x=10c---(2)
  Applying (1)/(2) we get
  (9x-9y)/(10y+x)=2c/10c
  (9x-9y)/(10y+x)=1/5
  =)45x-45y=10y+x
  =)44x=55y
  =)4x=5y=t(say)
  On solving x=5 and y=4
  Therefore age of A=54,Age of B=45 and age of C is 4.5 years.
• 10 years agoHelpfull: Yes(6) No(0)
• how may we identify the correct ans you dnt even mention the option for the answer
  everybody gives their own explanation and their answer
• 7 years agoHelpfull: Yes(3) No(0)