Q. In a simultaneous throw of pair of dice .find the probability of getting the total more than 7

• total cases = 36
  cases for more than 7 = 4,4 3,5 5,3 2,6 6,2 5,4 4,5 3,6 6,3 5,5 6,4 4,6 6,5 5,6 6,6
  
  = 15/36
  = 5/12 ans....
• 10 years agoHelpfull: Yes(23) No(0)
• 15/36...two dices are roled with each having 6 chances and so total 36 chances..
  favourable events(total >7=8,9,10,11,12)..8=(4,4),(2,6)(6,2)(5,3)(3,5)
  9=(4,5)(5,4)(6,3)(3,6)
  10=(5,5)(6,4)(4,6)
  11=(5,6)(6,5)
  12=(6,6)
  probability=15fav events/total 36 events =15/36=5/12
• 10 years agoHelpfull: Yes(7) No(0)
• total out comes-36
  possible out comes- (2,6) (3,5) (3,6) (4,4) (4,5) (4,6) (5,3) (5,4) (5,5) (5,6) (6,2) (6,3) (6,4) (6,5) (6,6) = 15
  PRB= 15/36 =5/12
• 10 years agoHelpfull: Yes(5) No(0)
• ans= 15 (2,6),(3,5),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)
• 10 years agoHelpfull: Yes(3) No(1)
• (2,6)(3,5)(3,6)(4,4)(4,5)(4,6)(5,3)(5,4)(5,5)(5,6)(6,2)(6,3)(6,4)(6,5)(6,6)=15
  ans:15/36=5/12
  
• 10 years agoHelpfull: Yes(1) No(0)
• total cases for two dice=36
  total more than 7 in simultaneous throw=(2,6),(6,2),(3,5),(5,3),(3,6),(6,3),(4,4),(4,5),(5,4),(4,6),(6,4),(5,5),(5,6),(6,5),(6,6)=15
  now the probability of getting total more than 7 is=15/36=5/12
• 10 years agoHelpfull: Yes(1) No(0)
• (6,2) (5,3) (4,4) (3,5) (2,6)
  (6,3) (5,4) (4,5) (3,6)
  (6,4) (5,5) (4,6)
  (6,5)(5,6)
  (6,6)
  Probability of getting more than 7 is=(15/36)=(5/12)
• 10 years agoHelpfull: Yes(1) No(0)
• 15/36 simple hai
  
• 10 years agoHelpfull: Yes(0) No(1)
• ans is 15/36
• 10 years agoHelpfull: Yes(0) No(0)
• total case=6*6=36
  getting sum more than 7 is=(3,5)(5,3)(5,4)(4,5)(5,6)(6,5)(6,6)(5,5)(4,4)(2,6)(6,2)(6,3)(3,6)(6,4)(4,6)=15
  so solution is=15/36=5/12
• 10 years agoHelpfull: Yes(0) No(1)
• Two dices are rolled -- So the total outcomes are 36(i.e 6*6)
  Now all the possible outcomes of getting the total more than 7 are,
  (2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)
  Therefore here they are 15 possibilties of getting the total more than 7
  Probability = Favourable events/Total outcomes = 15/36 = 5/12 --is the answer
• 5 years agoHelpfull: Yes(0) No(0)