100 coins are tossed. Probability of getting 50 heads is equal to probability of getting 51 heads. That probability is??

• p=probability of getting one head in one trail
  the total number of trails n=100
  then by using binomial dist with parameters n,p
  P(50)=p(51)
  ((1-p)/50)=(p/51)
  p=(51/101)
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• Ans:50/100=51/100
  1/2=51/100
  on equating ANS:2
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• tosses 100
  probability for a coin for tail=1/2
  similarly probability of getting 50 heads=50/100=1/2
  similarly probability of getting 51 heads=51/100=1/2
  49/100
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• plz give me correct ans
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• given probabiity of 50 and 51 heads are equal so,
  50/100=51/100
  
  51/100-50/100= 1/100 ans
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• by binomial distribution
  100c50(p)50(1-p)50=100c51(p)51(1-q)49
  =51/101
  
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