A can do a piece of work in 20 days while b can do the same work in 25 days. both of them together began the work and after 5 days b left. how many days would a take to finish the remaining work

• A 's 1 day work = 1/20
  B 's 1 day work = 1/25
  
  A + B's 1 day work = 1/20 + 1/25
  ------------------------>9/100
  
  A + B's 5 day work = 5 * 9/100
  ------------------------->9/20
  
  Remaining work = 1 - 9/20 == 11/20
  
  A ll complete d remaining work in
  
  11/20 * 20 = 11 days
  
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• a ll take 11 days to finish d remaining work
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• A's 1 day work = 1/20
  B's 1 day work = 1/25
  
  work done by both for 5 days = (1/20)+(1/25)*5
  = 9/20
  
  i.e. work completed by both of them in 5 days becomes == 9/20
  remaining work = 1- 9/20
  = 11/20
  
  a can complete the remaining work in (11/20)*(20/1)= 20 days.
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• sorry 11 days.
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