Suppose a person has a salary S in every 2 years the salary gets incremented by S/2. So how many years its going to take , to get S^2.


options : 1) 4S 2) 4(S-1) 3 & 4th option i don't remember.

• According to question,
  His salary will increase like this: S+ S/2+ S/2+ S/2+ S/2...
  
  So total salary we require: S^2
  
  Therefore,
  
  S^2 =S + n(S/2) ...where n= no . of terms S/2 = no. of 2-year gaps
  
  Solving the above equation:
  
  S=1+n(1/2) => n=2(s-1)
  
  therefore if n is number of '2-year gaps', then no. of years will be: 2*n
  
  =2*2(S-1)=4(S-1)
  
  Answer: (b) 4(S-1)
• 10 years agoHelpfull: Yes(11) No(6)
• salary to be incremented = s^2-s = s(s-1)
  salary increases in 2 years given s/2.
  thus no of 2 years required to be a salary of s^2 = [s(s-1)]/[s/2] = 2(s-1)
  thus total no of years required is 2*2(s-1) {since 2(s-1) is the no of 2 years that is required to hve a salary of s^2}
  thus 4(s-1) is the answer...:)
• 10 years agoHelpfull: Yes(6) No(3)
• it's 4(s-1).. solve this problem by taking s=2,3 &4.
• 10 years agoHelpfull: Yes(3) No(6)
• salary = 6rs.
  2 yrs increment = 3rs... takes 20 years time to reach 36 rs i.e. s^2
  20 = 4(6-1) =4(s-1)
  (2)
• 10 years agoHelpfull: Yes(3) No(1)
• find the value of n using this equation S^2 = S(1 + 1/2)^n
  answer will be 2 times of n.
• 10 years agoHelpfull: Yes(2) No(5)
• it will take 2s years because s/2*2s=s^2.
• 10 years agoHelpfull: Yes(1) No(7)
• it forms an A.P.
  s, s+ s/2, s+s/2+s/2 ...... s^2
  
  Now
  a+(n-1)d=s^2
  s+(n-1)s/2=s^2
  
  solving this we'll get n=2s-1
• 10 years agoHelpfull: Yes(1) No(0)
• rakesh bhai kya hoga solution
  bta do
  
• 10 years agoHelpfull: Yes(0) No(2)