Perimeter of the backwheel is 9 feet and front wheel is 7 feet at a certain distance. The front wheel gets 10 revolutions more than the back wheel. What is the distance?

• 315 feet
  
  If distance=d
  Number of revolutions by back wheel=d/9 & front wheel=d/7
  (d/7)-(d/9)=10 ,2d=630 ,d=315
• 10 years agoHelpfull: Yes(36) No(5)
• here
  7(x+10)=9(x)
  solving this eq
  we get x=35
  now total distance =9(35)=315 feet
  315
  
• 10 years agoHelpfull: Yes(9) No(0)
• since front wheel takes 10 more revolutions so it travels 70 feet in those extra number of revolutions.
  But distance travelled by front wheel is less by 2 feet as compared to rear wheel for each revolution. So this loss of 2 feet is covered by those extra revolutions taken by the front wheel.
  So 70 feet would have been created by 70/2=35 revolutions.
  So rear wheel travels 35 revolution (and front wheel takes 35+10=45 Revs.) So distance is 35*9 (or 45*7) = 315 feet
  
  
• 10 years agoHelpfull: Yes(7) No(0)
• Distance covered=perimeter× no of revolutions. Let the rare wheel makes x revolutions so front wheel makes x+10 revolutions .Hence equation for distance covered is : 7 (x+10)=9x. Solving this we get x= 35. Hence distance covered= 35×9=315.
• 10 years agoHelpfull: Yes(4) No(0)
• 315 ft.
  
  7(x+10)=9(x)
  solving this eq
  we get x=35
  now total distance =9(35)=315 feet
  315
• 10 years agoHelpfull: Yes(3) No(1)
• 315 feet
  (d/7)-(d/9)=10 ,2d=630 ,d=315
• 10 years agoHelpfull: Yes(1) No(1)
• 7(x+10)=9(x)
  solving this equation
  we get x=35
  now total distance =9(35)=315 feet
  315
• 10 years agoHelpfull: Yes(1) No(0)
• 315
  35*9 = 45*7
• 10 years agoHelpfull: Yes(0) No(1)
• 315, 7(x+10)=9x
  x=35, 7*45 or 9*35=315
• 10 years agoHelpfull: Yes(0) No(0)
• 7(x+10)=9(x)
  x=35
  total distance=9(35)=315
• 10 years agoHelpfull: Yes(0) No(0)