find the radius of circle inscribed in a circle whose sides are 8 cm,15 cm and 17 cm.

• It will be a triangle...
  S=(8+15+17)/2=20
  so, area of triangle, rootover(S(S-a)(S-b)(S-c))=60
  as we know there is another formula,
  area of triangle=rS, where r=radius of inscribed circle
  So 60=r*20
  So r= 3(ANS)
• 9 years agoHelpfull: Yes(52) No(0)
• first 8cm, 15cm, 17cm must be a triangle.
  then from the properties of incirle
  r^2=((s-a)(s-b)(s-c))/s
  now s=a+b+c/2=20
  r^2=3*3(after solving)
  so r=3cm
• 9 years agoHelpfull: Yes(4) No(1)
• There is a mistake in you question buddy...
• 9 years agoHelpfull: Yes(3) No(5)
• why do circle have sides ..
• 9 years agoHelpfull: Yes(2) No(2)
• I never knew a circle has sides.. And that too 3 !
• 9 years agoHelpfull: Yes(2) No(3)
• since 8^2+15^2=17^2
  this is the side of right angle triangle so area will be 1/2*8*15=60
  we have the formula radius=area of triangle/s(semi perimeter)
  s=8+15+17/2=20
  therefore r=60/20=3
  ans=3
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• given triangle is a right angle triangle, with perpendicular side 15 and 8
  so area = 60
  (s)half perimeter= 20
  we know
  r.s=area
  r.20=60
  r=3cm
• 9 years agoHelpfull: Yes(1) No(0)
• if the circle is inscribed
  
  BY HERONS FORMULA
  AREA WILL BE ROOT(20*3*5*12) = 60..
  AREA IS ALSO =r*s where r is incentre..
  r=3cm
  
  or
  
  if the circle is circumscribed then..
  area =a*b*c/4R wher Ris circumradius..
  R=8.5cm
• 8 years agoHelpfull: Yes(1) No(2)
• it must be A triangle
  
  
• 9 years agoHelpfull: Yes(0) No(3)
• i think there is a mistake in question. there must be a triangle in place of circle
• 9 years agoHelpfull: Yes(0) No(2)
• We know for right angle trinangle inradius r is given by bc/ a+b+c,a being hypotenuss and b and c other sides
  So 8*15/8+15+17
  8*15/40=3 ans
• 9 years agoHelpfull: Yes(0) No(0)
• 8 ,15,17. It must be a right angle triangle .
  so r = (base+perpendicular- Hypotenuse)/2
  r=3
• 1 year agoHelpfull: Yes(0) No(0)