a cow and a horse are bought for 200000.the cow is sold at a profit of 20% and horse at a loss of 10%.the overall gain is 4000.the cost price of the cow..??
70000
80000
120000
130000

• Cost price of cow is ₹80000.
  Let us assume the C.P of cow = x
  C.P of horse = y;
  Then according to the given condition x+y=200000 --------(1);
  
  Also the S.P of Cow = 1.2x
  S.P of horse = 0.9y
  So total S.P = 1.2x+0.9y
  
  Given,
  (1.2x+0.9y)-(x+y) = 40000 --------(2)
  
  Now two variable two equation, on solving we get x=80000
• 10 years agoHelpfull: Yes(10) No(0)
• let x be CP of cow
  profit from cow-loss from horse = 4000
  0.2x - 0.1(200000-x) = 4000
  x = 80000
• 10 years agoHelpfull: Yes(5) No(0)
• using alligation & mixture,
  p%=4000*100/20000=2%
  20%_______2%_______-10%
  12 18
  hence ratio is 2:3
  total sum of ratio=2+3=5
  cp of cow=2*200000/5=80000
  hence answer is 80000
  
• 10 years agoHelpfull: Yes(5) No(0)
• cp of cow and horse = 200000
  p% of cow = 20%
  l% of horse = 10%
  
  let cp of cow = x
  cp of horse = 200000-x
  
  overall gain = 4000
  therefore sp - cp =4000 --> 1
  
  sp = 120% of x + 90% of (200000-x)
  = 6x/5 + 180000 - 9x/10
  = 3x/10 + 180000
  substitute sp in eqn 1 and cp=200000(given)
  
  3x/10 + 180000 - 200000 = 4000
  3x/10 - 20000 = 4000
  
  solving x= 80000 (ans cp of cow)
  
• 10 years agoHelpfull: Yes(4) No(0)
• ans 80000
  let cost price of cow =x and horse =y
  then x+y=200000
  now cow sold at 20% profit and horse at 10% loss
  so 6x/5 + 9y/10 = 204000
  therefore 12x+9y=2040000
  solving these two equations we get price of cow x = 80000
• 10 years agoHelpfull: Yes(2) No(0)