If p is greater than q, then which of the following is true?
1) 0.9^p=0.9^q
2) 0.9^p>0.9^q
3) 9^p>9^q

• Since p>q so (9)^p>(9)^q
• 9 years agoHelpfull: Yes(13) No(0)
• option 3 is right.
  say p=2 , q=1 then 0.9^2=0.81 while, 0.9^1=0.9.
  and 9^2=81 whereas 9^1=9.
• 9 years agoHelpfull: Yes(7) No(0)
• clearly 3rd option is true!!!
• 9 years agoHelpfull: Yes(1) No(0)
• 3 is true
  
• 9 years agoHelpfull: Yes(1) No(0)
• 0.9^p>0.9^q beause p is greater than q
• 9 years agoHelpfull: Yes(0) No(5)
• 9^p>9^q
  explanation:p is greater than q.so 0.9^p will be not equal to 0.9^q.if you assign values for p as 2 and q as 1 then it is clear dat option 3 is correct.
• 9 years agoHelpfull: Yes(0) No(0)
• 9^p>9^q, as given that p>q ,assume p=2 and q=1 ie. 9^2>9^1 = 81>9
• 9 years agoHelpfull: Yes(0) No(0)
• option 3
  let us assume p to be 3 and q to be 2 (p is greater than q)
  then 729>81
• 9 years agoHelpfull: Yes(0) No(0)
• p>q so (9)^p>(9)^q
• 9 years agoHelpfull: Yes(0) No(0)
• 3) since 9>1
• 9 years agoHelpfull: Yes(0) No(0)
• 3rd option is true
  
• 9 years agoHelpfull: Yes(0) No(0)
• Option 3 is true
• 9 years agoHelpfull: Yes(0) No(0)
• (753*753+247*247-753*247)/(753*753*753+247*247*247)
  here 753=a;247=b
  so,
  (a^2+b^2-ab)/(a^3+b^3)=1/(a+b) [a^3+b^3=(a^2+b^2-a*b)(a+b)]
  =1/1000 ans..
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• It can also be : 0.9^p < 0.9^q
• 9 years agoHelpfull: Yes(0) No(1)
• option 3 is correct
  9^p>9^q
• 9 years agoHelpfull: Yes(0) No(0)
• 3 assume p and q
• 9 years agoHelpfull: Yes(0) No(0)