How many integers x satisfy the equation
(x^2 - x - 1 )^(x+2) =1
1) 3
2) 2
3) 4
4) none of these

• 3) 4
  (x+2)=0 => x=-2
  x^2 - x - 1 = 1 => x = 2,-1
  x^2 - x - 1 = -1 => x = 0,1 but at x=1 no soln.
  
  4 integral solns
  x= -2,-1,0,2
• 9 years agoHelpfull: Yes(26) No(3)
• (2,0,-1) ------->[by trial method]
  
  these are the integers that solve the above equation.... therefore the answer is option 1) 3
• 9 years agoHelpfull: Yes(1) No(5)
• put n=2
  (4-2-1)^4
  then by solving above we get 1
  ans 2
  
• 9 years agoHelpfull: Yes(1) No(3)
• only 3 integers satisfy this condition
  2,-1 and 0.
  for x=1;(1^2-1-1)^(1+2)
  => (1-2)^3 or (-1)^3=-1.
• 9 years agoHelpfull: Yes(1) No(2)
• no of integer will satisfy the equation is 3.
  put x=2,-1,0.
  by putting all these value it will satisfy the equation.so no of integer is 3.
• 9 years agoHelpfull: Yes(0) No(5)
• 2) 2
  (-2,1) only these two numbers are satisfying the condition
• 9 years agoHelpfull: Yes(0) No(4)
• 4 integers satisfy the equation
  they are
  -1,1,0,2
• 9 years agoHelpfull: Yes(0) No(2)
• 4 x=0,2,-1,-2
• 9 years agoHelpfull: Yes(0) No(0)
• log is on base 10
  (x+2)log(x^2-x-1)=0
  (x+2)=0, log(x^2-x-1)=0
  x=-2
  x^2-x-1=10^0
  x^2-x-1=1
  x^2-x-2=0
  x=-1,x=2
  hence ans=2,-1,2
• 9 years agoHelpfull: Yes(0) No(0)
• 4 is answer
  
  2-.-1,0,2
• 9 years agoHelpfull: Yes(0) No(0)
• 4 is answer
  
  2-.-1,0,2
• 9 years agoHelpfull: Yes(0) No(0)
• submit n check every option in place of x .if the value L.H.S and R.H.S are equal
• 9 years agoHelpfull: Yes(0) No(0)