TCS
Company
Numerical Ability
Log and Antilog
In how many ways seven letter between A & B can be arranged from alphabets so that there is no repetition?
Read Solution (Total 5)
-
- remaining letters other than A & B (26-2) =24
24p7 for arrangement of seven letters btwn A & B and 2! for A & B itself
ans:
24p7*2! - 10 years agoHelpfull: Yes(15) No(1)
- 24*23*22*21*20*19*18
- 10 years agoHelpfull: Yes(4) No(3)
- Between A and B 7 position can filled with 7 letter that can come from 24 different letter in 24p7 different way.And 7 letter can permute among themselves in 7! different way.And A and B can permute among them in 2! way.So total way 24p7*7!*2!.
- 10 years agoHelpfull: Yes(4) No(0)
- 24P7 *2
first arrange 7 letters between a b. 24p7 ways
then multiply by 2 because a and b can be interchanged - 10 years agoHelpfull: Yes(2) No(1)
- Right Answer is 24P7*2*18!
Cos we also have to arrange letters in between ie
CDEFGHI
DEFGHIJ
.
.
.
upto
18., - 10 years agoHelpfull: Yes(1) No(1)
TCS Other Question