What is the value of x is real number ?
(1) x^2 + 1 = 1/(x^2 + 1)
(2) x^3 + x^2 = 0
Mark A if question can be answered by using one of the statements alone, but cannot be answered by usingthe other statements alone
Mark B if question can be answered by using either statements alone
Mark C if question can be answered by using both statements together, but cannot be answered by using either statements alone
Mark D if question can not be answered even by using both statements together

• Ans = A
  from statement 1-
  (x^2+1)^2=1
  x^2+1=+-1
  now x^2+1=1,,,so x=0
  and x^2+1=-1,,,,,,so x=(-2)^1/2 (It is not possible )
  from statement 2-
  x^3+x^2=0
  x^2(x+1)=0
  so x=0 & -1(both r real )
  here value of x is not clear .
  
  so statement-1 is sufcnt
• 10 years agoHelpfull: Yes(35) No(10)
• ans is B
  both eq can ans alone
• 10 years agoHelpfull: Yes(24) No(5)
• my solun is right bcz i got marks on this question
• 10 years agoHelpfull: Yes(7) No(1)
• since in question they are not asking exact value of x
  and here from both equn we can find that value of x are are real
  from eq 1-
  (x^2+1)^2=1
  x^4+2x^2+1-1=0
  X^2(x^2+2)=0
  either x^2=0, or x^2=-1
  since x^2=-1 does not exist, so real value is 0,
  
  Now from eq 2
  x^3+x^2=0
  X^2(x+1)=0
  either x^2=0, or x=-1
  
  hence ans should be b
• 10 years agoHelpfull: Yes(4) No(4)
• B) It can be answered by anyone of the options.
• 10 years agoHelpfull: Yes(2) No(1)
• statement 1-
  x^2+1=1/x^2+1
  =>(x^2+1)^2=1
  this gives x=0 or x=(-2)^1/2
  
  statement 2-
  x^3+x^2=0
  =>x^2(x+1)=0
  this gives x=0 or x=-1.
  so we different solution for the value of x....
  therefore ans is (d)....the question cannot be answered by using both d statements.
• 10 years agoHelpfull: Yes(2) No(5)
• b.......
  question can b answered by referring both equations alone..
  
• 10 years agoHelpfull: Yes(1) No(0)
• (1) x^2+1 = 1/(x^2+1)
  (X^2+1)^2 = 1
  x^2+1 = +1 or x^2+1 = -1
  x^2 = 0 or x^2 = -2 (cant be possible)
  x=0.....:)
  
  (2) X^3+X^2= 0
  x^2(x+1)= 0
  x=0 or x=-1 possible
  ans will be (B)
• 10 years agoHelpfull: Yes(1) No(0)
• both are required
  
• 10 years agoHelpfull: Yes(0) No(2)
• B
  both equations can solve the problem.
  
• 10 years agoHelpfull: Yes(0) No(0)
• from eq 1-
  (x^2+1)^2=1
  x^4+2x^2+1-1=0
  X^2(x^2+2)=0
  either x^2=0, or x^2=-1
  since x^2=-1 does not exist, so real value is 0,
  
  Now from eq 2
  x^3+x^2=0
  X^2(x+1)=0
  either x^2=0, or x=-1
  here both are real.
• 10 years agoHelpfull: Yes(0) No(0)
• (x^2+1)^2=1, x^2+1=+-1,x=0 only
• 10 years agoHelpfull: Yes(0) No(0)
• Ans is B : x can be solved from either of the statements...
• 10 years agoHelpfull: Yes(0) No(1)
• B..
  using both stmnts we can calculate the value of x
• 9 years agoHelpfull: Yes(0) No(0)
• A is the right answer as using 2nd equation answer can not be found............... :P
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is A
• 9 years agoHelpfull: Yes(0) No(0)
• Ans: A
  
  
  
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• A because using the expression 1 we get imaginary value of x
  
• 9 years agoHelpfull: Yes(0) No(0)
• from 1st we will get x=square root of i that is complex
  so alone by 2nd x=-1
  hence A
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is both statements are needed becoz statement 1 gives 2 solution and statement 2 gives 2 solution . But one solution is common i.e. x=0
• 8 years agoHelpfull: Yes(0) No(0)