Two alternative packages A and B are available for processing a database having 10k records.Package A requires 0.0001n2 time units and package B requires 10nlog10n time units to process n records.What is the smallest value of k for which package B will be preferred over A?
A. 12
B. 10
C. 6
D. 5

• option c 6 will be ans
  
  package A requires time= 0.0001n^2
  put n=10^k
  =0.0001*(10^k)^2
  =10^-4 *10^2k
  =10^2k-4
  now Times for Package B=10nlog10n
  put n=10^k
  =10*10^k*(log10*10^k)
  =10^k+1*(log10^k+1)
  =10^k+1*(k+1log10)
  =10^k+1*k+1
  so for package A time will be =10^2k-4
  B =k+1(10^k+1)
  put k=6
  A=10^8
  B=7*10^7
  that means B prefer than A Because it contains less amout of time.
• 10 years agoHelpfull: Yes(21) No(1)
• mr. ravi if i put 12,10 then also, we get A>B so now which is correct
  
• 10 years agoHelpfull: Yes(1) No(0)
• @piyush.... question here is to find the SMALLEST value of k so the answer will be 6 whether 10 & 12 are both satisfying the equations.
• 9 years agoHelpfull: Yes(1) No(0)
• for n=10
  time for A=0.01
  time for B=100
• 10 years agoHelpfull: Yes(0) No(1)
• why cant u put 5 as the right answer???????
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
• 9 years agoHelpfull: Yes(0) No(0)