Peter and paul are 2 friends.Sum of their ages is 35 years.Peter is twice as old as paul was when peter was as old as paul is now.What is the present age of peter?

• Supposing Peter’s age is e and Paul’s age is a
  
  We have a + e = 35………………….. (1)
  
  Now when Peter was Paul’s age which means (e - a) years ago
  
  Peter would have been e - (e - a) = a which is Paul’s age now
  
  Paul would have been a - (e - a) = 2a - e
  
  
  We have been given that Peter’s age is twice what Pauls was,
  
  so e = 2(2a - e) = 4a - 2e which gives 3e = 4a………………….. (2)
  
  For ease of use if a + e = 35; then 3a + 3e = 105 = 3a + 4a from (2) above
  
  Thus 7a = 105
  
  a = 15; e = 20
  
  So Peter is 20 years and Paul is 15 years. The sum is 35 years and when Peter was 1
• 14 years agoHelpfull: Yes(11) No(5)
• Present age of Peter is 21.
  Solution : Present age of Peter = 21. Present age of Paul = 14. Sum = 35.
  When Peter was as old as Paul is now, i.e 14, Paul was 7. So Peter was twice old as Paul that time.
• 14 years agoHelpfull: Yes(4) No(14)
• let the age of peter and paul was X and Y z years ago.
  after z years the sum of age is 35 hence...
  X+Y+2Z=35
  peter was twice old as Pual in the past hence
  X=2Y
  in the present paul is as old as peter was that time hence ...
  X=Y+Z
  solving the three equation we get the age of peter z time ago
  x=14;
  that is now equal to paul age.
  peter age=35-14
  peter=21
• 14 years agoHelpfull: Yes(3) No(6)
• If we take peter 20 & paul 15;
  then 5 years ago peter would be 15..paul 10
  but at that time 15 != 2(10)
  so 20 could not be the right ans.
  it should be 21 & 14
  bcs 7 years ago 14 & 7
  14=2(7)
  
• 12 years agoHelpfull: Yes(2) No(1)