IBM
Company
Numerical Ability
Age Problem
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
1) 2 times
2) 5/2 times
3) 11/4 times
4) 3times
Read Solution (Total 2)
-
- Ronit present age x years
then father present= x+3x=4x
now, after 8 years
4x+8=5/2(x+8)..> 8x+16=5x+40....> x=8
now required ratio = 4x+16/x+16 =48/24 =2
Ans is 2 - 9 years agoHelpfull: Yes(6) No(0)
- 0.01x+100+x
1.01x+100 - 11 years agoHelpfull: Yes(1) No(1)
IBM Other Question