The sum of the first 100 numbers, 1 to 100 is divisible by

• 
  Sum of first 100 number is = 100/2(100+1) = 5050.
  
  Ans. is B. 2.
  
  Note:
  1. Why not divisible by 4. The last two digit (here, 50) is not divisible by 4
  2. Why not divisible by 8. The last three digits should be 0's or divisble by 8. Doesnt work here.
  3. Why not by 6. Divisibility by 6 means, it should be divided by 2 and 3. Yes, we knwo, itsi dviisble by 2, what about 3. For it to be divisible by e, the sum of the numbers should be divisible by 3. Here it doesnt work. So, 6 is off.
• 12 years agoHelpfull: Yes(1) No(0)
• y not by 5...usasay bhi toh divisible hai na..!!
• 10 years agoHelpfull: Yes(1) No(0)
• n(n+1)/2=100(100+1)/2
  =5050
  hence 5050 is divisible by 2
• 7 years agoHelpfull: Yes(0) No(0)