Wipro Company Numerical Ability Time and Work

X and Y can do a piece of work n 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of work. How long did the work last?

Read Solution (Total 2)

To simplify, Let the work be 60 units(L.C.M of 20 and 12)
X can complete in one day=60/20=3units
Y can complete in one day=60/12=5Units
Both together can complete in one day=8units
Since X has completed 4 days of work, he must have completed 12 units of work
The remaining work that is 48 units of work has to be completed by both together
Thus, Both can complete the work in 48/8=6 days.
13 years agoHelpfull: Yes(6) No(2)

x 1 day work=1/20
y 1 day work=1/12
x 4days work=4/20=1/5
work left=1-1/5=4/5
now (x+y)1 day work=(1/12+1/20)=8/60
4/5 work done by them in=(4/5)*(60/8)=6 days
total days=6+4=10days..
11 years agoHelpfull: Yes(2) No(2)

Wipro Other Question

A can finish a work in 24 days, B n 9 days and C in 12 days. B & C start the work but are forced to leave after 3 days. The remaining work done by A in? A does 4/5 of work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?