Sixteen men can complete a work in twelve days. Twenty four children can complete the same work in 18 days. 12 men and 8 children started working and after eight days three more children joined them. How many days will they now take to complete the remaining work?
(A) 2 days (B) 4 days ( C) 6 days (D) 8 days

• Ans : (B) 4 days
  one day work of 16 men is 1/12
  one day work of 24 children is 1/18
  1 man's one day work is 1/(12*16 )
  1 child 's one day work is 1/(24*18)
  one day work of 12 men and 8 children = 12*one day work of one man + 8* one day work of one child
  hence one day work of 12 men and 8 children = ((12/12*16)+(8/24*18))
  one solving
  one day work =(35/54*8)
  work done in 8 days is 8* one day work = 8*(35/54*8) = 35/54
  remaining work = 1-35/54 = 19/54
  the remaining work is done by 12 men and 11 children
  their one day work is 12*one men's oneday work + 11 * one child's one day work
  hence 12*(1/12*16) + 11*(24*18)
  
  one day work * number of days to complete remaining work = remaining work
  
  ((1/16)+(11/24*18)) * X = 19/54
  one solving
  X = 4
  hence the work is done in 4 days
  
• 12 years agoHelpfull: Yes(7) No(4)
• ans 4
  16m*12=24c*18 m/c=9/4
  total work= 16*9*12
  (12*9+8*4)*8+(12*9+11*4)*x=16*9*12
  x=608//152=4
• 8 years agoHelpfull: Yes(2) No(5)