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Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is
option
a) 1
b) 3
c) 4
d) 0
Read Solution (Total 4)
-
- 1
- 14 years agoHelpfull: Yes(4) No(1)
- 1
- 14 years agoHelpfull: Yes(4) No(1)
- 4
- 14 years agoHelpfull: Yes(4) No(2)
- it will be 1 ,i.e. is circumcenter.
- 14 years agoHelpfull: Yes(2) No(2)
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