A bucket contains z drops. and it leaks x drops in t secs.then the time required to empty the bucket(in minutes)?

• leakage of x drop in t sec.So in 60 sec(1 min.)=60x/t drops
  Therefor for leakage of z drops=z/(60x/t)= zt/60x min.
  
• 12 years agoHelpfull: Yes(37) No(0)
• x drops are leaked in t seconds.
  so, 1 drop is leaked in t/x second.
  Therefore, z drops are leaked in t*z/x seconds
  Now, 1 minute equals 60 seconds.
  Hence, 1/60 minutes equal 1 second.
  So, t*z/(60*x) minutes are required to empty the bucket.
• 12 years agoHelpfull: Yes(30) No(0)
• x drop in tsec
  1 drop in t/x
  z drop in z*t/x
• 11 years agoHelpfull: Yes(4) No(2)
• leaks x drops in t secs means 1 drop will take X/T seconds
  
  Z drops will take ZX/T seonds
  time required to empty the bucket(in minutes) is ZX/(60*T)
• 13 years agoHelpfull: Yes(2) No(9)
• x drops are leaked in t seconds.
  so, 1 drop is leaked in t/x second.
  Therefore, z drops are leaked in t*z/x seconds
  Now, 1 minute equals 60 seconds.
  Hence, 1/60 minutes equal 1 second.
  So, t*z/(60*x) minutes are required to empty the bucket.
• 12 years agoHelpfull: Yes(2) No(0)
• final Ans---> zt/60x mins
  
• 10 years agoHelpfull: Yes(2) No(0)
• time to empty the bucket = z*t/x
• 10 years agoHelpfull: Yes(2) No(0)