Travelling at 3/4th the speed a man is 20 minutes later then speed is??

• Let L be the distance, V be his usual speed.
  We have L/(3/4 V) = L/V + 20.
  So, 4/3 * L/V = L/V + 20,
  Or 1/3 * L/V = 20,
  we get L/V = 60 (min)
• 10 years agoHelpfull: Yes(31) No(10)
• suppose L be the dist., V be his normal speed.now L/(3/4 V) = L/V + 20.
  So, 4/3 * L/V = L/V + 20,
  Or 1/3 * L/V = 20,
  we get L/V = 60 (min)
  but this is time for normal speed i.e.,t=60 and the other time t'=60+20=80 min.
  now v-v'= 1-3/4 =1/4
  so .. L/60-L/80=1/4 HENCE L=6 KM
  SO, v = 6km/60 min or, 6km/h
• 10 years agoHelpfull: Yes(17) No(2)
• unless and until distance is mentioned speed can not be determined
• 10 years agoHelpfull: Yes(3) No(10)
• d=s*t
  now speed is 3/4 th of orginal means tym is 4/3 th of originl (coz s ~1/t) that means tym taken extra is 4/3 -1 =1/3 th of original and it is equal to 20 min so 1/3 * ori =20 => ori =60 min thnk u . this is the fastest process to solve this kind of sums
  
• 10 years agoHelpfull: Yes(3) No(1)
• v=d/t
  1/4x=1/t=60/20
  x=12 km/hr
• 10 years agoHelpfull: Yes(2) No(13)
• wkt speed=1/t or t=1/s
  Assume actual speed=x
  1/x-4/3=20/60
  x=(3/7)*60
  x=25.71 km/m.
  
• 11 years agoHelpfull: Yes(0) No(25)