Find the probability that a five digit no formed by 1,2,3,4,5 ( not repeated) are
divisible by 4.

• a number is divisble by 4 only when the last 2 digit can be divided by 4..and so in this case it is possible when last two digits are 12,32,24,52.and for that the probability will be 24/120=1/5...
• 12 years agoHelpfull: Yes(11) No(9)
• last two digits must be,
  ***12
  ***24
  ***32
  ***52
  case1) ***12
  rest three digits can be filled in 3*2*1 or 6 ways
  similarly,
  case2) ***24
  6 ways
  case3) ***32
  6ways
  case4) ***52
  6 ways
  total required ways = 6*4 = 24
  total arrangements = 5*4*3*2*1 = 120
  
  probability = 24/120 = 1/5
• 10 years agoHelpfull: Yes(7) No(0)
• digits which r divisble by 4 are 12,24,32,52 (last 2 digits should divided by 4)
  4!/5! = 24/120 =1/5...............
• 12 years agoHelpfull: Yes(5) No(2)
• 24/120 how?
• 12 years agoHelpfull: Yes(4) No(2)
• digits which r divisble by 4 are 12,24,32,52 (last 2 digits should divided by 4)
  then remaining digits r 3 ...(3!*2!*1!)*4 (possibilities)=48
  so,prob=48/5! (total 5 digits nos)
  ans=2/5
  
• 10 years agoHelpfull: Yes(2) No(4)
• N^n-1
  N=no of digits in series
  n=no of digits to ask
  ans=625
• 12 years agoHelpfull: Yes(0) No(7)
• (n-1)!/n!=?
  (5-1)!/5!=24/120=1/5
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• 24/120=1/5
• 9 years agoHelpfull: Yes(0) No(0)
• 5!*4!*3!*2!*1
• 6 years agoHelpfull: Yes(0) No(0)